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A ball (mass 0.40 kg) is initially moving to the left at 30 m/s. After hitting the wall, the ball is moving to the right at 20 m/s. What is the impulse of the net force on the ball during its collision with the wall?

Respuesta :

Answer:

Impulse, J = 20 m/s  

Explanation:

Given that,

Mass of the ball, m = 0.4 kg

Initial speed of the ball, u = -30 m/s (left)    

Final speed of the ball after hitting, v = 20 m/s (right)

Let J is the impulse of the net force on the ball during its collision with the wall. The change in momentum of an object is equal to the impulse imparted to it. It is given by :

[tex]J=m(v-u)[/tex]

[tex]J=0.4\ kg(-30-20)\ m/s[/tex]

J = -20 m/s

So, the magnitude of impulse of the net force on the ball during its collision with the wall is 20 m/s.

asuwafohjames

The impulse on the ball is 20 Ns.

What is impulse?

This can be defined as the product of force and time. The impulse of a force acting on a body is also equal to the change in momentum of the body

To calculate the impulse of the net force on the ball during the collision, we use the formula below.

Formula:

  • I = m(v-u)............ Equation 1

Where:

  • I = Impulse on the ball
  • v = Final velocity of the ball
  • u = Initial velocity of the ball
  • m = mass of the ball.

From the question,

Given:

  • m = 0.40 kg
  • v = 20 m/s
  • u = -30 m/s (to the right)

Substitute these values into equation 1

  • I = 0.40[20-(-30)]
  • I = 0.40(20+30)
  • I = 0.40(50)
  • I = 20 Ns.

Hence, the impulse on the ball is 20 Ns.

Learn more about impulse here: https://brainly.com/question/25700778

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