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A person with mass mp = 71 kg stands on a spinning platform disk with a radius of R = 1.62 m and mass md = 193 kg. The disk is initially spinning at ω = 1.8 rad/s. The person then walks 2/3 of the way toward the center of the disk (ending 0.54 m from the center). 1)What is the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk?

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Answer:

439.587 kgm²

Explanation:

[tex]m_p[/tex] = Mass of person = 71 kg

R = Radius of platform = 1.62 m

[tex]m_d[/tex] = Mass of disc = 193 kg

The moment of inertia of the system is given by

[tex]I=m_pR^2+\frac{1}{2}m_dR^2\\\Rightarrow I=71\times 1.62^2+\frac{1}{2}\times 193\times 1.62^2\\\Rightarrow I=439.587\ kgm^2[/tex]

The total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk is 439.587 kgm²

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