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A wood-burning stove (emissivity = 0.900 and surface area = 3.75 m2) is being used to heat a room. The fire keeps the stove surface at a constant 182 °C (455 K) and the room at a constant 22 °C (295 K). Determine the net radiant power generated by the stove.

Respuesta :

Answer:

Radiated power will be [tex]675241.7175watt[/tex]

Explanation:

We have given emissivity [tex]\epsilon =0.9[/tex]

Stove temperature T = 455 K

Room temperature [tex]T_C=295K[/tex]

We know the Stephan's constant [tex]\sigma =5.67\times 10^{-6}w/m^2K^4[/tex]

We know that radiated power is given by [tex]P=\epsilon \sigma A(T^4-T_C^4)=0.9\times5.67\times 10^{-6}\times  3.75\times (455^4-295^4)=675241.7175watt[/tex]

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