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5. RELATING IDEAS Carbon and oxygen react to form
carbon monoxide: 2C+02-→ 2CO. What mass-
es of carbon and oxygen are needed to make
56.0 g CO? Which law does this illustrate?

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Answer:

5. It is one of the most important greenhouse gases linked to global warming, but it is a minor component of Earth’s atmosphere (about 3 volumes in 10,000), formed in combustion of carbon-containing materials, in fermentation, and in respiration of animals and employed by plants in the photosynthesis of carbohydrates.

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The mass of oxygen and carbon required to produce 56 grams CO has been 32 grams and 24 grams respectively. The law that illustrates this has been the law of conservation.

The moles of product or reactant in a chemical reaction are given by the stoichiometric coefficient of the balanced chemical equation.

The given balanced equation has been:
[tex]\rm 2\;C\;+\;O_2\;\rightarrow\;2\;CO[/tex]

Computation for mass of oxygen and carbon

From the balanced chemical equation, for the formation of 2 moles of CO,1 mole of oxygen and 2 moles of carbon has been required.

56 g of CO has been equivalent as:

[tex]\rm Moles=\dfrac{Mass}{Molar\;mass} \\\\Moles\;CO=\dfrac{56}{28}\;mol\\\\ Moles\;CO=2\;moles[/tex]

The moles of CO produced has been 2 moles. Thus, the moles of oxygen and carbon required are:

  • Oxygen required =  1 mole

The mass of oxygen required is 32 grams.

  • Carbon required is 2 moles.

The mass of carbon required has been 24 grams.

The law that illustrates this is the law of conservation. According to the law of conservation, mass has not been lost in the chemical reaction.

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