gracemariehill10
contestada

A sample of glucose is found to have 34.92 g of carbon, 5.87 g of hydrogen and 46.56 g of oxygen. Another sample is found to have 0.4471 g of carbon, 0.07510 g of hydrogen, and 0.5962 g of oxygen. Show that these results are consistent with the law of definite proportions.

Respuesta :

Answer:

See explanation below.

Explanation:

You just need to show that the ratio of all elements within the compound is always the same. The easiest way to do this is to divide everything by the lowest mass in each group:

[tex]34.92 C : 5.87H : 46.56O \rightarrow \frac{34.92}{5.87} C : \frac{5.87}{5.87}H : \frac{46.56}{5.87}O \rightarrow 6C : 1H : 8O\\\\0.4471 C : 0.0751H : 0.5962O \rightarrow \frac{0.4471}{0.0751} C : \frac{0.0751}{0.0751}H : \frac{0.5962}{0.0751}O \rightarrow 6C : 1H : 8O\\[/tex]

**Please keep in mind that this ratio is DIFFERENT from the stoichiometric ratio of the elements within the compound and does not tell you the empirical formula. The ratio just says there are 6g of C for every 1g of H and 8g of O. It does NOT mean the empirical formula is C6HO8.

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