alex7190
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At a high school with 300 students, 32 play soccer, 18 play basketball, and 10 play both sports. If a student is selected at random, find the probability that a student plays soccer or basketball.

Respuesta :

PhillSwift

Answer:

P(student plays both soccer or basketball)= 40/300

Simplify : 2/15

In a group of 300 students, 18 students play basketball, 11 students play football. 10 students play both sports.

Now, A student is chosen randomly from this group.

What is the probability that the student plays both soccer or basketball?

Probability of any event=no. of favorable outcomes/total no. of outcomes

 Here, no. of favorable outcomes

=no. of students who plays both soccer or basketball

=  32+18-10

= 40

and, total no. of outcomes= 300

If a student is selected at random, the probability that a student plays soccer or basketball is  [tex]\frac{2}{15}[/tex]

To start, we list the variables given

32 ----- Soccer

18 ---- Basketball

10 ----- Basketball + Soccer

If you look at the question, it was stated that 10 people plays basketball and soccer. The keyword being "and". While we are asked to find the probability that a student plays basketball or soccer. This then means that we add the number of people playing basketball together with those playing soccer.

32 + 18 = 40.

Probability of a student playing soccer or basketball is then 40/300 = 2/15

learn more about probability here https://brainly.com/question/23044118

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