A 2 liter closed container holds 1 mole of an ideal gas at a certain temperature and pressure. Which closed container will hold 3 moles of this ideal gas at the same temperature and pressure?

Respuesta :

The 3 liters closed container.

Explanation:

We have the ideal gas law:

PV = nRT

where:

P =  pressure

V = volume

n = number of moles

R = gas constant

T = temperature

The number of moles n₁ (which is 1 mole) from the 2 liter (V₁) container are equal to:

n₁ = PV₁ / RT

The number of moles n₂ from the second container ( (V₂) are equal to:

n₂ = PV₂ / RT

From the data given in the problem we know that:

n₂ =  3 × n₁

We replace the n's:

PV₂ / RT =3 × PV₁ / RT

(PV₂ / RT) × (RT / P) = 3 × V₁

V₂ = 3 × V₁

V₂ = 3 × 2

V₂ = 6 liters

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ideal gas law

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