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The equation [tex]2m^{2}-1m-8=0[/tex] has solutions of the form

M= N +or- sqaure root of D/over M


Solve this equation and find the appropriate values of N,M,and D. Do not worry about simplifying the √D portion of the solution.


N= M= D=

Respuesta :

sqdancefan

Answer:

  • N = 1
  • M = 4
  • D = 65

Step-by-step explanation:

The given equation is of the form ...

  ax² +bx +c = 0

where a=2, b=-1, c=-8.

The quadratic formula gives the solution to the above equation as ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

So, for your equation, the solution is ...

  [tex]m=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(2)(-8)}}{2(2)}=\dfrac{1\pm\sqrt{65}}{4}[/tex]

Comparing this to the form ...

  [tex]m=\dfrac{N\pm\sqrt{D}}{M}[/tex]

we see ...

  • N = 1
  • M = 4
  • D = 65

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