Answer:
[tex]\large\boxed{y>\dfrac{c-ax}{b}}\\\text{for}\ a>0,\ b>0,\ c>0[/tex]
Step-by-step explanation:
[tex]ax+by>c\qquad\text{subtract}\ ax\ \text{from both sides}\\\\ax-ax+by>c-ax\\\\by>c-ax\qquad\text{divide both sides by}\ b\ (\text{we can, because}\ b>0)\\\\\dfrac{by}{b}>\dfrac{c-ax}{b}\\\\y>\dfrac{c-ax}{b}[/tex]