Answer:
Step-by-step explanation:
[tex]\bold{METHOD\ 1:}[/tex]
[tex]\triangle ABC\sim\triangle DE F\qquad(\text{similar tringles)}\\\\\text{Therefore corresponding sides are in proportion:}\\\\\dfrac{BA}{AC}=\dfrac{ED}{DF}\\\\\text{Substitute}\ BA=360,\ AC=600,\ ED=30\\\\\dfrac{360}{600}=\dfrac{30}{DF}\qquad\text{cross multiply}\\\\360DF=(600)(30)\\\\360DF=18000\qquad\text{divide both sides by 360}\\\\DF=50[/tex]
[tex]\bold{METHOD\ 2:}[/tex]
[tex]\text{Use the Pythagorean theorem:}\\\\leg^2+leg^2=hypotenuse^2\\\\\text{We have}\ leg=40,\ leg=30,\ hypotenuse=DF.\\\\\text{Substitute:}\\\\40^2+30^2=DF^2\\\\1600+900=DF^2\\\\2500=DF^2\to DF=\sqrt{2500}\\\\DF=50[/tex]