Answer:
(a) The rate at which ammonia being formed = 0.0493 M/s
(b) The rate at which molecular nitrogen reacting = 0.0247 M/s
Explanation:
[tex]N_{2}+3H_{2}\longrightarrow2NH_{3}[/tex]
The rate at which molecular hydrogen is reacting = [tex]\frac{d}{dt}[H_{2}]=0.074\:M/s[/tex]
The rate of the above reaction can be expressed as:
[tex]rate=-\frac{d}{dt}[N_{2}]=-\frac{1}{3} \frac{d}{dt}[H_{2}]=\frac{1}{2}\frac{d}{dt}[NH_{3}][/tex]
(a) [tex]\frac{d}{dt}[NH_{3}]=\frac{2}{3}(0.074)=0.0493[/tex]
The rate at which ammonia being formed = 0.0493 M/s
(b) [tex]-\frac{d}{dt}[N_{2}]=\frac{1}{3}(0.074)=0.0247[/tex]
The rate at which molecular nitrogen reacting = 0.0247 M/s
