The final speed of the car is 2) 150 m/s
Explanation:
Since the motion of the car is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem, we have
u = 10 m/s
[tex]a=1.5 m/s^2[/tex]
s = 7,467 m
Solving for v, we find the final velocity (and speed) of the car:
[tex]v=\sqrt{u^2+2as}=\sqrt{10^2+2(1.5)(7,467)}=150 m/s[/tex]
Learn more about accelerated motion:
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