Respuesta :

skyluke89

1) The frequency of the clock is 4 Hz

2) The period of the clock is 0.25 s

Explanation:

1)

In a periodic motion, the frequency of the motion is equal to the number of complete cycles per second.

Mathematically:

[tex]f=\frac{N}{t}[/tex]

f is the frequency

N is the number of cycles completed in a time t

For the clock in this problem, we have

N = 88 (number of cycles)

t = 22 s (time interval)

Substituting,

[tex]f=\frac{88}{22}=4 Hz[/tex]

2)

The period of a periodic motion is the time taken for one complete oscillation to occur.

Mathematically, the period is equivalent to the reciprocal of the frequency:

[tex]T=\frac{1}{f}[/tex]

where

T is the period

f is the frequency

Here we have found

f = 4 Hz

So, the period of the clock is

[tex]T=\frac{1}{4}=0.25 s[/tex]

Learn more about frequency and period:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

nuhulawal20

The frequency and period of the clock is 4Hz and 0.25s respectively.

Given the data in the question;

Number of cycles; [tex]N = 88[/tex]

Time interval; [tex]t = 22s[/tex]

Frequency; [tex]f = \ ?[/tex]

Period; [tex]T = \ ?[/tex]

Frequency is the number of complete cycles occurring per period of time.

Frequency; [tex]f = \frac{N}{t}[/tex]

We substitute in our given values

[tex]f = \frac{88}{22s} \\\\f = 4s^{-1}\\\\f = 4Hz[/tex]

Therefore, the frequency of the clock is 4Hz

Frequency [tex]f[/tex] is also the reciprocal of the period [tex]T[/tex]:

Hence, [tex]T = \frac{1}{f}[/tex]

We substitute in our values

[tex]T = \frac{1}{4s^{-1}} \\\\T = 0.25s[/tex]

Therefore, the period of the clock is 0.25s

Learn more; https://brainly.com/question/9077368

Otras preguntas