Answer:
33.06 Kgm/s
Explanation:
Given information
Initial velocity= 20 m/s
mass, m=0.9 Kg
[tex]0.5\times 0.9\times v^{2}=0.5\times 0.7\times 0.9 Kg\times 20^{2}[/tex]
[tex]v^{2}=280[/tex]
[tex]v=\sqrt {280}=16.7332 m/s[/tex]
Here, v is -16.7332 m/s in opposite direction
Change in momentum
[tex]\triangle p= m(v-u)=0.9(-16.7332-20)=-33.0599 Kgm/s\approx -33.06 Kgm/s[/tex]
Therefore, the magnitude of change in momentum is 33.06 Kgm/s
