Answer:
Option A that is [tex]99.34[/tex] is the correct choice.
Step-by-step explanation:
To find what percentage of carbon-14 is still remaining after [tex]55[/tex] years.
We have to pull the equation and instead of [tex]t[/tex] we will put the years in numbers that is [tex]t=55[/tex]
Lets see the equation.
[tex]C(t)=100.e^{-0.000121(t)}[/tex]
Now to find the carbon-14 percentage.
Putting the value of [tex]t[/tex] in years.
So
[tex]C(t)=100.e^{-0.000121(t)}[/tex] and [tex]e^{-0.000121(55)}=0.9934[/tex]
[tex]C(t)=100\times 0.9934 =99.34[/tex]
As mentioned that the function is already framed to find the percentage we need not to convert it or multiply with [tex]100[/tex].
So the percentage of C-14 remaining after [tex]55[/tex] years is [tex]99.34[/tex]
Option A is the correct choice.
