The smallest integer is 1 and middle integer is 2 and largest integer is 3
Given that , three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.
We have to find the three consecutive integers
So, let the smallest integer be n, then the next two consecutive middle and largest integers will be n + 1, n + 2 respectively
Then, by the given statement,
Three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.
[tex]\begin{array}{l}{3 \times (n+2)+2=5 \times n+3 \times (n+1)} \\\\ {3 n+6+2=5 n+3 n+3} \\\\ {8=5 n+3} \\\\ {5 n=8-3} \\\\ {n=1}\end{array}[/tex]
Thus the smallest integer = n = 1
Middle integer = n + 1 = 1 + 1 = 2
Largest integer = n + 2 = 1 + 2 = 3
