Respuesta :
Hello,
Answer B
Let x the first number
x+2 the second
x*(x+2)=2115
==>x²+2x-2115=0
==>x=45 or x=-47
==>(x=45 and x+2=47) or (x=47 and x+2=-45)
Answer B
Let x the first number
x+2 the second
x*(x+2)=2115
==>x²+2x-2115=0
==>x=45 or x=-47
==>(x=45 and x+2=47) or (x=47 and x+2=-45)
Answer:
x² + 2x - 2,115 = 0
Step-by-step explanation:
Two consecutive odd integers looks like x+2. consecutive numbers are x+1. (odd numbers skip by 2 numbers. like between 5 and 7 is 2. )
SOOOO....
Now we can start. The product of two consecutive odd integers looks like
x(x+2) and it equals 2, 115 ---> x(x+2)=2,115
solve left side: x^2 +2x = 2,115
then move 2115 to left side to have a quadratic equation (make it equal to zero)
now we have:
x^2 +2x -2,115=0
that is you answer!
Hope it helps! ;)