Respuesta :
Hello,
A cubic polynomial with -2,1,2 as roots is
f(x)=k*(x+2)(x+1)*(x-2)=k(x²-4)(x+1)=k(x^3+x²-4x-4)
Looking the answers ==>k=1
==>Answer A
A cubic polynomial with -2,1,2 as roots is
f(x)=k*(x+2)(x+1)*(x-2)=k(x²-4)(x+1)=k(x^3+x²-4x-4)
Looking the answers ==>k=1
==>Answer A
Answer:
[tex]f(x)=x^3+x^2-4x-4[/tex]
Step-by-step explanation:
Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 2, negative 1, and 2
x intercepts are -2, -1, 2
We write the x intercepts in factor form
f(x)= (x-p)(x-q)(x-r)
where p, q and r are the x intercepts
f(x)= (x-(-2))(x-(-1))(x-2)
f(x)= (x+2)(x+1)(x-2)
now we multiply the parenthesis using FOIL method
(x+2)(x+1)= x^2 +2x+x+2= x^2+3x+2
[tex]f(x)= (x^2+3x+2)(x-2)[/tex]
now we multiply with (x-2)
x^3-2x^2 +3x^2-6x+2x-4
combine like terms
[tex]f(x)=x^3+x^2-4x-4[/tex]