The midpoint of the segment with the following endpoint (−4,−4) and (−9,5) is [tex]\left(\frac{-13}{2}, \frac{1}{2}\right)[/tex]
Solution:
Given, two points are (-4, -4) and (-9, 5)
We have to find the midpoint of the segment formed by the given points.
Now, we know that, mid point of a segment formed by [tex]\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)[/tex] is given by:
[tex]\text { Mid point } m=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)[/tex]
[tex]\text { Here in our problem, } x_{1}=-4, y_{1}=-4, x_{2}=-9 \text { and } y_{2}=5[/tex]
[tex]\text { Then, mid point } m=\left(\frac{-4+(-9)}{2}, \frac{-4+5}{2}\right)=\left(\frac{-4-9}{2}, \frac{-4+5}{2}\right)=\left(\frac{-13}{2}, \frac{1}{2}\right)[/tex]
Hence, the mid point of the segment is [tex]\left(\frac{-13}{2}, \frac{1}{2}\right)[/tex]
