The final velocity of the plane is 70.7 m/s.
Explanation:
The plane is moving at constant acceleration, so we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the plane in this problem, we have
s = 500 m
[tex]a=5.0 m/s^2[/tex]
u = 0 (the plane starts from rest)
So, solving for v, we find its final velocity:
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(5.0)(500)}=70.7 m/s[/tex]
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