Answer:
[tex]x=-\frac{3}{2}, x=1[/tex]
Step-by-step explanation:
[tex]2x^2+x-1=2[/tex]
Subtract 2 from both sides and factor:
[tex]2x^2+x-1=2\\2x^2+x-3=0\\(2x+3)(x-1)=0[/tex]
Solve each factor individually:
[tex]2x+3=0\\2x=-3\\x=-\frac{3}{2}[/tex]
[tex]x-1=0\\x=1[/tex]