Answer:
7500 ml
Step-by-step explanation:
The total volume of the mixture is 10 liters.
If the volume of the acid with 48% concentration is x liters and that of the acid with 80% concentration is y liters, then
x + y = 10 - 2 = 8 ........ (1) {Since 2 liters of distilled water is added to the mix}
If the final mix is of 40% concentration, then we can write
[tex]\frac{0.48x + 0.8 y}{x + y +2} = \frac{40}{100}[/tex]
⇒ 0.48x + 0.8y = 0.4x + 0.4y + 0.8
⇒ 0.08x + 0.4y = 0.8
⇒ 8x + 40y = 80
⇒ x + 5y = 10 ....... (2)
Now, solving equations (1) and (2) we get,
8 - y + 5y = 10, ⇒ 4y = 2, ⇒ y = 0.5 liters
Hence, from equation (1), x = 8 - 0.5 = 7.5 liters.
Therefore, 7.5 liters i.e. 7500 milliliters of 48% acid was used. (Answer)
