After completely factoring, we get:
(x + 6)(x - 2)(x + 2)
Further explanation:
Factorization is done by factor method or by synthetic division we will use the factor method to factorize the given expression.
Given
[tex]x^3+6x^2-4x-24\\Taking\ x^2\ and\ -4\ common\\=x^2(x+6)-4(x+6)\\=(x^2-4)(x+6)\\Using\ formula\ a^2-b^2=(a+b)(a-b)\ , we\ will\ factorize\ x^2-4\\So,\\=(x-2)(x+2)(x+6)[/tex]
After completely factoring, we get:
(x + 6)(x - 2)(x + 2)
Keywords: Cubic polynomial, factorization
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