14.87 g
We are given;
Volume as 0.5 liters
Molarity as 0.35 M
We are required to calculate the mass of the solute NaNO₃
Step 1 : Find the number of moles of the solute NaNO₃
Moles = Molarity × Volume
Moles = 0.35 M × 0.5 L
= 0.175 moles
Step 2: Mass of the solute NaNO₃
Mass is calculated by multiplying the number of moles by the molar mass of the compound.
Molar mass of NaNO₃ = 84.9947 g/mol
Therefore;
Mass of NaNO₃ = 0.175 moles × 84.9947 g/mol
= 14.874 g
= 14.87 g
Thus, the mass of the salt solute is 14.87 g