Answer:
d: 39W
Explanation:
Power(P) = w/t = F*d/t = F*v = m*a*v= 2*9.8*2 = 39.2W
The power required to lift a 2 kg mass at a speed of 2 m/s is 39 W.
Answer: Option D
Explanation:
Power required to lift a mass of about 2 kg will be equal to work done attained by the object per unit time. And, the mass (m) of the object is given as 2 kg and speed (v) as 2 m/s, then
[tex]\text { Power }=\frac{\text {work done }(w)}{\text { time }(t)}[/tex]
And, we know the following formula,
[tex]w=\text { Force } \times \text { distance}[/tex]
[tex]\text {Force}=m \times \text {acceleration}[/tex]
[tex]\text {velocity}=\frac{\text {distance}}{\text {time}}[/tex]
By applying this into the power equation, we get,
[tex]\text { Power }=m \times \text { acceleration } \times \text { velocity }=2 \times 9.8 \times 2=39.2 \mathrm{W}[/tex]
Hence, the power required to lift a mass, the rounded value would be 39 W.
