Answer:
Step-by-step explanation:
y+1=-3(x-5)
y + 1 = -3x + 15
y = -3x + 15 - 1
y = -3x + 14
Slope m1 = -3
The required line is perpendicular to this y+1=-3(x-5)
so. m1 * m2 = -1
-3*m2 = -1
m2 = -1/-3 = 1/3
Slope = 1/3; pass through (4, -6)
y -y1 = m(x-x1)
y - [-6] = 1/3 (x - 4)
y + 6 = 1/3 (x - 4)
y + 6 = 1/3x - 4/3
y = 1/3x - 4/3 +6 {-4/3 + 6 = -4/3 + 6*3/1*3 =-4/3+18/3 =(-4+18)/3 = 14/3}
y= 1/3x - 14/3