The values of p for which the equation px = 10 have a solution −5; 1; 20 is -2, 10, [tex]\frac{1}{2}[/tex]
Solution:
Given, equation is px = 10.
We have to find the values of p for which solutions of given equations becomes -5, 1, 20.
We just need to substitute -5, 1, 20 in given equation as x, to values of p.
Now, For -5 ⇒ p(-5) = 10 ⇒ -5p = 10 ⇒ p = -2
For 1 ⇒ p(1) = 10 ⇒ p = 10
For 20 ⇒ p(20) = 10 ⇒ 20p = 10 ⇒ p = [tex]\frac{1}{2}[/tex]
Hence, the values of p are -2, 10, [tex]\frac{1}{2}[/tex] for the solutions -5, 1, 20 respectively.
