Find the equation of a line parallel to −4x−5y=−4 that contains the point (3,−2). Write the equation in slope-intercept form.

Respuesta :

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange - 4x - 5y = - 4 into this form

Add 4x to both sides

- 5y = 4x - 4 ( divide all terms by - 5 )

y = - [tex]\frac{4}{5}[/tex] + [tex]\frac{4}{5}[/tex] ← in slope- intercept form

with slope m = - [tex]\frac{4}{5}[/tex]

Parallel lines have equal slopes, thus

y = - [tex]\frac{4}{5}[/tex] x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - [tex]\frac{12}{5}[/tex] + c ⇒ c = - 2 + [tex]\frac{12}{5}[/tex] = [tex]\frac{2}{5}[/tex]

y = - [tex]\frac{4}{5}[/tex] x + [tex]\frac{2}{5}[/tex] ← in slope- intercept form

Answer:

Step-by-step explanation:

M=-4/5