Answer:
.98
Step-by-step explanation:
1-(35/43)^18 im in stats too tehee
Answer:
The probability that at least one of the students select a president who died in office is 0.97541 or 97.541%
Step-by-step explanation:
Consider the provided information.
Mr. Bray prepares a list of 43 US presidents, 8 of whom died in office.
Therefore, [tex]p=\frac{8}{43}[/tex]
If 8 out of 43 died in office then the number of president who didn't died in office is 43-8=35
[tex]q=\frac{35}{43}[/tex]
Let X be the number of president who died in office.
The probability that at least one of the students select a president who died in office is:
[tex]P(X\geq 1)=1-P(X=0)[/tex]
[tex]P(X\geq 1)=1-^{18}C_0(\frac{8}{43})^0(\frac{35}{43})^{18}[/tex]
[tex]P(X\geq 1)=1-(\frac{35}{43})^{18}[/tex]
[tex]P(X\geq 1)=1-0.02459[/tex]
[tex]P(X\geq 1)=0.97541[/tex]
Hence, the probability that at least one of the students select a president who died in office is 0.97541 or 97.541%
