60 = x + x + 1 + x + 2
60 = 3x + 3
-3
57 = 3x
/3
19 = x
The 3 integers are: 19, 20, and 21.
Answer: 19, 20, and 21
Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 60 and it asks us to find the integers.
Three consecutive integers can be represented as followed.
X ⇒ first integer
X + 1 ⇒ second integer
X + 2 ⇒ third integer
Since the sum of our 3 consecutive integers is 60, we can set up an equation.
X + X + 1 + X + 2 = 60
3x + 3 = 60
-3 -3
3x = 57
÷ 3 ÷ 3
X = 19
X + 1 = 20
X + 2 = 21
Therefore, our three consecutive integers are 19, 20, and 21.
