Answer:
Explanation:
R = ρ L / S
ρ is resistivity , L is length of wire and S is cross sectional area
R at 20 degree
= [tex]\frac{5.25\times10^{-8}\times17\times10^{-2}}{3.14\times(.6\times10^{-3})^2}[/tex]
R₁ = 78.95 x 10⁻⁴ Ω
Resistivity at 120 degree
= 5.25 x 10⁻⁸ ( 1 + 5.25 x 10⁻⁸ x .0045 x 100)
= 7.61 x 10⁻⁸
Resistance at 120 degree
= [tex]\frac{7.61\times10^{-8}\times17\times10^{-2}}{3.14\times(.6\times10^{-3})^2}[/tex]
R₂= 114.44 x 10⁻⁴ Ω
Potential difference at 20 degree
= current x resistance
= 12.5 x 78.95 x 10⁻⁴
= 986.875 x 10⁻⁴ V
Electric field at 20 degree
= Potential diff / length
= 986.875 x 10⁻⁴ / 17 x 10⁻²
= 58 x 10⁻² V/m
Potential difference at 120 degree
= current x resistance
= 12.5 x 114.44 x 10⁻⁴
= 1430.5 x 10⁻⁴ V
Electric field at 120 degree
= Potential diff / length
= 1430.5 x 10⁻⁴ / 17 x 10⁻²
= 84.15 x 10⁻² V/m
A ) Maximum electric field = 84.15 x 10⁻² V/m
B ) 114.44 x 10⁻⁴ Ω
C ) 1430.5 x 10⁻⁴ V
