Answer:
0.01448
Step-by-step explanation:
Given that a man claims to have extrasensory perception (ESP).
No of times a fair coin is tossed = 26
No of correct predictions = 19
Let X be the no of correct predictions for x without esp just by mere guess
p = Prob for guess correct = 0.5 and q = 0.5
[tex]P(X\geq 19) = 26C19 (0.5)^{19} (0.5)^{7}+26C19 (0.5)^{20} (0.5)^{6}+...+26C26 (0.5)^{26} (0.5)^{0} \\\\=0.01448[/tex]
This will be the probability for getting atleast 19 correct without any ESP