Respuesta :
Answer:
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinatios of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
So, the binomial probability distribution has two parameters, n and p.
In this problem, we have that [tex]n = 1000[/tex] and [tex]p = \frac{700}{1000} = 0.7[/tex]. So the parameter is
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
The parameter from the question given out of the number of those surveyed and those who said they would support the extra holiday is defined;
Option A; p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
This is a binomial probability distribution problem.
We are given the sample size of n = 1000
We are also told that 700 students will support the extra holiday.
Now, the formula for binomial probability distribution is;
P(X = x) = ⁿCₓ × pˣ × q⁽ⁿ ⁻ ˣ⁾
Where;
p is probability of success
q is probability of failure
n is the number of trials
From this question, p = 700/1000 which will be the population proportion
Now, looking at the given options, we can conclude that the correct one that corresponds with our answer is Option A.
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