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Alpha particles, each having a charge of 2e and a mass of 6.64 ×10-27 kg, are accelerated in a uniform 0.80-T magnetic field to a final orbit radius of 0.30 m. The field is perpendicular to the velocity of the particles. How long does it take an alpha particle to make one complete circle in the final orbit?

Respuesta :

Answer:

1.63 x 10^-7 second

Explanation:

charge, q = 2 e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

mass, m = 6.64 x 10^-27 kg

Magnetic field, B = 0.80 T

radius, r = 0.30 m

Time period , T = ?

[tex]T = \frac{2\pi m}{Bq}[/tex]

By substituting the values

[tex]T = \frac{2\times 3.14\times 6.64\times 10^{-27}}{0.8\times 3.2 \times 10^{-19}}[/tex]

T = 1.63 x 10^-7 second

Thus, the time to take one circular round is 1.63 x 10^-7 second.

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