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In a lab experiment, two identical gliders on an air track are held together by a piece of string, compressing a spring between the gliders. While they are moving to the right at a common speed of 0.420 m/s, one student holds a match under the string and burns it, letting the spring force the gliders apart. One glider is then observed to be moving to the right at 1.300 m/s. (the string and spring both have negligible mass). What velocity does the other glider have? Enter a positive value if the velocity is toward right and enter a negative value if the velocity is toward left.

Respuesta :

Answer:

[tex]v_{1f}[/tex] = -0.460 m/s

Explanation:

To solve this problem we will use the concept of moment, write the initial amount when they are united and the end

Initial. Before break away

    p₀ = (m + m) v₀

Final. After separating

    [tex]p_{f}[/tex] = m [tex]v_{1f}[/tex] + m [tex]v_{2f}[/tex]

   p₀ = [tex]p_{f}[/tex]

   (m + m) v₀ = m [tex]v_{1f}[/tex] + m [tex]v_{2f}[/tex]

They tell us that when they go together the speed vo = 0.420 m / s and after separating one we will call 2 has a speed of v2f = 1,300 m / s. let's look for each other's speed

    m [tex]v_{1f}[/tex] = (2m) vo - m [tex]v_{2f}[/tex]

    [tex]v_{1f}[/tex] = 2 v₀ - [tex]v_{2f}[/tex]

    [tex]v_{1f}[/tex] = 2 0.420 - 1.300

   [tex]v_{1f}[/tex] = -0.460 m/s

The negative sign indicates that it moves to the left

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