Answer:
c < a = b
Explanation:
to arrange tensile stress from smallest to largest
tensile stress = [tex]\sigma = \dfrac{F}{A}[/tex]
a) A rod 50.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.
[tex]\sigma = \dfrac{F}{A}[/tex]
[tex]\sigma = \dfrac{200}{1}[/tex]
[tex]\sigma = 200\ Mpa[/tex]
b) A rod 25.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.
[tex]\sigma = \dfrac{F}{A}[/tex]
[tex]\sigma = \dfrac{200}{1}[/tex]
[tex]\sigma = 200\ Mpa[/tex]
c) A rod 20 cm long with cross-sectional area 2.00 mm² and with a 100 N force applied on each end.
[tex]\sigma = \dfrac{F}{A}[/tex]
[tex]\sigma = \dfrac{100}{2}[/tex]
[tex]\sigma = 50\ Mpa[/tex]
hence the order comes out to be
c < a = b
