[tex]N= 170 turns\\A=10.9cm^2\\t=3.5*10^{-2}s \\\B = 5.6*10^{-5}T[/tex]
The Magnetic flow [tex]\Phi_{initial}[/tex] is given by the formula,
[tex]\Phi_{Initial}=BAsin\theta[/tex]
Replacing the values
[tex]\Phi_{Initial} =(5.6*10^{-5})(10.9)(\frac{10^{-4}m^2}{1cm^2}) sin90\°[/tex]
[tex]\Phi_{Initial} =6.104*10^{-7} Wb[/tex]