Answer:
The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.
Explanation:
[tex]ClO (g) + O_3 (g)\rightarrow Cl (g) + 2O_2 (g) ,\Delta H_{rxn,1}= -122.8 kJ/mol[/tex]..[1]
[tex]2O_3 (g) \rightarrow 3O_2 (g) \Delta H_{rxn,2}= -285.3 kJ/mol[/tex]..[2]
[tex]O_3(g) + Cl (g)\rightarrow ClO(g) + O_2 (g) \Delta H_{rxn,3} = ?[/tex]...[3]
Applying Hess's law:
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[2] - [1] = [3]
[tex]\Delta H_{rxn,3} =\Delta H_{rxn,2} -\Delta H_{rxn,1} [/tex]
[tex]=-285.3 kJ/mol-(-122.8 kJ/mol)=-162.5 kJ/mol[/tex]
The enthalpy of reaction when chlorine reacts with ozone is -162.5 kJ/mol.