Respuesta :
Answer:
v = 123.15 m/s
Explanation:
It is given that,
Total impulse provided by the model rocket, J = 25 N.s
Mass of the rocket, m = 0.203 kg
To find,
The speed with which it was launched
Solve,
According to Impulse- momentum theorem, the relationship between the impulse and the momentum is given by :
[tex]J=F.t=m\Delta v[/tex]
[tex]J=F.t=m(v-u)[/tex] (u = 0 at rest)
[tex]J=mv[/tex]
[tex]v=\dfrac{J}{m}[/tex]
[tex]v=\dfrac{25\ N.s}{0.203\ kg}[/tex]
v = 123.15 m/s
Therefore, the speed of the rocket when it was launched is 123.15 m/s.
Answer:
123.15 m/s
Explanation:
Impulse = 25 Ns
mass of rocket, m = 0.203 kg
Initial velocity of rocket, u = 0 m/s
Let the rocket achieved the speed of v.
Impulse = change in momentum
Impulse = m (v - u)
25 = 0.203 (v - 0)
25 = 0.203 v
v = 123.15 m/s
Thus, the rocket achieved the speed of 123.15 m/s.
