The firm's Cobb-Douglas production function is given as: Q (L comma K )equals L to the power of 0.75 end exponent K to the power of 0.25 end exponent Based on this information, the marginal product of capital (MPK) is:________

Respuesta :

Answer:

The marginal product of capital (MPK) is [tex]0.25(\frac{L}{K})^{0.75}[/tex]

Step-by-step explanation:

Data provided in the question:

The firm's Cobb-Douglas production function is given as

⇒ Q = [tex]L^{0.75}K^{0.25}[/tex]

Now,

To find the marginal product of capital (MPK) computing the partial derivation of the Cobb-Douglas production function

i.e

[tex]\frac{\partial Q}{\partial K} =\frac{\partial (L^{0.75}K^{0.25})}{\partial K}[/tex]

here, term L will be constant as it is a partial derivation with respect to K

thus,

[tex]\frac{\partial Q}{\partial K} =0.25L^{0.75}K^{0.25-1}[/tex]

or

[tex]\frac{\partial Q}{\partial K} =0.25L^{0.75}K^{-0.75}[/tex]

or

[tex]\frac{\partial Q}{\partial K} =0.25(\frac{L}{K})^{0.75}[/tex]

Hence,

the marginal product of capital (MPK) is [tex]0.25(\frac{L}{K})^{0.75}[/tex]