Two ice skaters, Skater X and Skater Y, are at rest on a horizontal surface made of ice. The friction between the ice and the skaters is negligible. Skater X, who has a smaller mass than Skater Y, pushes Skater Ysuch that Skater Y travels with a speed of 2vo to the right. Which of the following indicates the direction of the velocity of Skater X and the direction of the velocity of the center of mass of the two-skater system after the push?

Both skaters here known to be the system were initially at rest to imply that even their masses were at rest. Once skater X pushes skater Y, he moves to the left to conserve total momentum of the system and the center of mass remains at rest since the system hasn’t experienced any external force. Therefore, the total linear momentum of the system remains conserved. Consequently, the velocity of center of mass changes when external force is applied. Moreover, the center of mass remains at rest since it was initially at rest.

ahirohit963 ahirohit963 · Answer 2 · 2021-10-25T08:05:59+02:00

The correct option is b) Skater X to the left and Center of mass zero.

Given :

The friction between the ice and the skaters is negligible.

Skater X has smaller mass than Skater Y.

Speed of Skater Y = [tex]\rm 2v_0[/tex]

Solution :

The system were initially at rest to imply that Skater X and Skater Y masses were at rest. Once skater X pushes Skater Y, he moves to the left to conserve total momentum of the system and the center of mass remains at rest since the system hasn’t experienced any external force. Therefore, the total linear momentum of the system remains conserved. Consequently, the velocity of center of mass changes when external force is applied. Moreover, the center of mass remains at rest since it was initially at rest. Therefore, the correct option is b) Skater X to the left and Center of mass zero.

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