Step-by-step explanation:
Given [tex]T=\frac{10x^{2} }{y}[/tex].
We need to evaluate [tex]logT[/tex]. Let us apply logarithm on both sides of the above equation.
[tex]logT=log(\frac{10x^{2} }{y})[/tex]
We know that [tex]log(ab)=log(a)+log(b)[/tex] and [tex]log(\frac{a}{b})=log(a)-log(b)[/tex], [tex]log(a^{b})=(b)log(a)[/tex].
Hence, [tex]logT=log10+log(x^{2})-log(y)[/tex]
∴ [tex]logT=1+2log(x)-log(y)[/tex]
