Answer:
-50.09 kJ/mol
Explanation:
Let ΔGrxn be
ΔGrxn = ΔGrxn° + RT ln{[ADP][HPO₄²⁻]/[ATP]}
Given:
ΔGrxn = -30.5 × 10³
R = 8.314
T = 37°c = 310k
[ATP] = (5.0 × 10⁻³) M,
[ADP] = (0.50 × 10⁻³) M,
[HPO₄²⁻] = (5.0 × 10⁻³) M :
We have:
ΔGrxn
= (-30.5 × 10³) + (8.314) × (310) × ln{(0.50 × 10⁻³) × (5.0 × 10⁻³) / (5.0 × 10⁻³)} J/mol
= −50,090 J/mol
= -50.09 kJ/mol