Respuesta :
Answer:
A.) 34.866 x 10¯23 g/atom
B.) 2.64 x 10^22 atoms in 1 cm3
C.) 1 atoms per unit cell
Explanation:
A) Calculate the average mass of one atom of polonium:
210g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 34.866 x 10¯23 g/atom
B) Determine atoms in 1 cm3:
9.19g / 34.866x 10¯23 g/atom = 2.64 x 10^22 atoms in 1 cm3
Determine volume of the unit cell:
(3.37 x 10¯8 cm)3 = 3.827 x 10¯23 cm3
Determine number of unit cells in 1 cm3:
1 cm3 / 3.827 x 10¯23 cm3 = 2.61 x 1022 unit cells
C) Determine atoms per unit cell:
2.64 x 1022 atoms / 2.61 x 1022 unit cells = 1 atoms per unit cell
2.64 x 10²² polonium atoms are in exactly 1 cm³, 2.61 x 1022 unit cells are in exactly 1cm³ and one polonium atom is present in one unit cell.
What is cubic unit cells?
Unit cell is the simplest repeating structure of any body, so as the name suggested cubic unit cells are the repeating units of cubic structure.
In the question, given that:
Density of polonium = 9.19 g/cm³
Length of unit cell = 3.37 Å or 3.37 × 10⁻⁸ cm
(a). To calculate the no. of polonium atoms in 1 cm³, first we have to determine the average mass of one atom and that will be calculated as follow:
210g per mol ÷ 6.022 x 1023 atoms per mol = 34.866 x 10¯²³ g/atom
Now, we will divide the given mass to the average mass of one atom:
9.19g / 34.866x 10¯²³ g/atom = 2.64 x 10²² atoms in 1 cm³.
(b). To determine the no. of unit cells are in exactly 1 cm³ unit cells, calculation is as follow:
1 cm³ / (3.37 × 10⁻⁸ cm)³ = 2.61 x 1022 unit cells
(c). No. of polonium atoms in per unit cell is calculated as follow:
2.64 x 10²² atoms / 2.61 x 10²² unit cells = 1 atom per unit cell
Hence, polonium atoms are in exactly 1 cm³ is 2.64 x 10²², 2.61 x 1022 unit cells are in exactly 1cm³ and one polonium atom is present in one unit cell.
To learn more about cubic unit cell, visit below link:
https://brainly.com/question/8305059