Answer:
The potential difference is 121.069 V
Solution:
As per the question:
Diameter of the cylinder, d = 9.0 cm = 0.09 m
Length of the cylinder, l = 40 cm = 1.4 m
Average Resistivity, [tex]\rho = 5.5\ \Omega-m[/tex]
Current, I = 100 mA = 0.1 A
Now,
To calculate the potential difference between the hands:
Cross- sectional Area of the Cylinder, A = [tex]\pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}[/tex]
Resistivity is given by:
[tex]\rho = R\frac{A}{l}[/tex]
[tex]R = \rho \frac{l}{A}[/tex]
[tex]R = 5.5\times \frac{1.4}{6.36\times 10^{- 3}} = 1210.69\ \Omega[/tex]
Now, using Ohm's Law:
V = IR
[tex]V = 0.1\times 1210.69 = 121.069\ V[/tex]