Answer:
Time period = 41654.08 s
Explanation:
Given data:
Internal volume is 210 m^3
Rate of air infiltration [tex]9.4 \times 10^{-5} kg/s[/tex]
length of cracks 62 m
air density = 1.186 kg/m^3
Total rate of air infiltration [tex]= 9.4\times 10^{-5} \times 62 = 582.8\times 10{-5} kg/s[/tex]
total volume of air infiltration[tex] = \frac{582.8\times 10{-5}}{1.156} = 5.04\times 10^{-3} m^3/s[/tex]
Time period [tex]= \frac{210}{5.04\times 10^{-3}} = 41654.08 s[/tex]
