Answer:
+17 kg m/s
Explanation:
Question is missing. Found it on google:
"What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg?"
Solution:
we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:
[tex]p_i = p_f\\p_b+p_p=p_b'+p_p'[/tex]
where
[tex]p_b = +30 kg m/s[/tex] is the momentum of the ball before the collision
[tex]p_p = 0[/tex] is the momentum of the pin before the collision (zero because the pin is stationary)
[tex]p_b' = +13 kg m/s[/tex] is the momentum of the ball after the collision
[tex]p_p'[/tex] is the momentum of the pin after the collision
Solving the equation for [tex]p_p'[/tex], we find:
[tex]p_p' = p_b + p_p - p_b' = +30 +0 -(+13)=+17 kg m/s[/tex]
