Answer:
d)myints [1] = something.
Explanation:
The elements in the array are stored serially.Every element in the array is indexed and the indexing start form 0 to size-1.So to access the second element in the array it's index will be 1.So to access the second element we have to write arrayname[1];
In our case the name of the array is myints.
Hence the answer is myints[1]=something