Answer:
speed of air is 200 m/s
Explanation:
given data
length dl = 10 m
diameter dp = 2 m
maximum allowable speed Vp = 10 m/s
scale [tex]\frac{Dp}{Dm}[/tex] = 1/20th
to find out
speed of air in the tunnel to achieve dynamic similarity
solution
we know in dynamic similarity ratio of force at corresponding point in model are equal and different dimensionless no is use for dynamic similarity
so
Rem = Rep
Re is modal law
so
[tex]( \frac{\rho VD}{\mu}) p= (\frac{\rho VD}{\mu} ) m[/tex]
and
VpDp = VmDm
so [tex]\rho p = \rho m[/tex]
[tex]\mu p = \mu m[/tex]
so
10 × [tex]\frac{Dp}{Dm} = Vm[/tex]
Vm = 200 m/s
so speed of air is 200 m/s