Answer:
(a) 24.49 m/s
(b) 289.8 s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Given:
u = 10 m/s
a = 0.05 m/s²
s = 5 km = 5000 m ( 1 km = 1000 m)
Considering - Equation of motion
[tex]v^2-u^2=2as[/tex]
Applying values as:
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 0.05\times 5000+10^2}\\\Rightarrow v=24.49\ m/s[/tex]
Considering - Equation of motion
[tex]v=u+at[/tex]
Applying values as:
[tex]v=u+at\\\Rightarrow 24.49=10+0.05t\\\Rightarrow t=\frac{24.49-10}{0.05}=289.8\ s[/tex]
